What is the axis (y-0)^2=4x-4 ?

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axis (y-0)^2=4x-4

axis

(y - 0)^{2} = 4 x - 4

y = 0

Solution steps

(y - 0)^{2} = 4 x - 4

Rewrite

(y - 0)^{2} = 4 x - 4

in the standard form:

4 \cdot 1 \cdot (x - 1) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (1, 0), p = 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 12 x (x - 4)

x - 2 = (y - 1)^{2}

y = 6 x^{2} - 29 x - 5

y = 3 x^{2} + x - 6

x^{2} + 4 x - 4 y + 5 = 0