What is the axis y=-2x^2-4x-7 ?

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axis y=-2x^2-4x-7

axis

y = - 2 x^{2} - 4 x - 7

x = - 1

Solution steps

y = - 2 x^{2} - 4 x - 7

Rewrite

y = - 2 x^{2} - 4 x - 7

in the standard form

4 (- \frac{1}{8}) (y - (- 5)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 5), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = 9 x^{2} - 2

y = x^{2} - 7 x + 12

y \geq x^{2}

y = 5 (x + 2)^{2} - 3

y = - \frac{1}{2} x^{2} - 5 x - \frac{15}{2}