What is the axis x^2-4x-8y-12=0 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis x^2-4x-8y-12=0

axis

x^{2} - 4 x - 8 y - 12 = 0

x = 2

Solution steps

x^{2} - 4 x - 8 y - 12 = 0

Rewrite

x^{2} - 4 x - 8 y - 12 = 0

in the standard form

4 \cdot 2 (y - (- 2)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 2), p = 2

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

x^{2} + 2 x - 8 y + 33 = 0

y = (8 - 2 x)^{2}

y = 7 - 6 x^{2}

x^{2} - y = 4

y = - x^{2} + 18 x - 79