What is the axis y=-x^2+18x-79 ?

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axis y=-x^2+18x-79

axis

y = - x^{2} + 18 x - 79

x = 9

Solution steps

y = - x^{2} + 18 x - 79

Rewrite

y = - x^{2} + 18 x - 79

in the standard form

4 (- \frac{1}{4}) (y - 2) = (x - 9)^{2}

Therefore parabola properties are:

(h, k) = (9, 2), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 9

y = 12 x^{2} + 8 x - 15

x^{2} + 12 x + y + 40 = 0

y^{2} + 4 x = 7

y = 8 x - 2 x^{2}

y = - 6 x^{2} + 600 x - 5726