What is the axis x=4y^2 ?

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axis x=4y^2

axis

x = 4 y^{2}

y = 0

Solution steps

x = 4 y^{2}

Rewrite

x = 4 y^{2}

in the standard form:

4 \cdot \frac{1}{16} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 2 x^{2} + 9 x - 3

y = 36 x - 9 x^{2}

y = 5 x^{2} - 8 x + 3

y = x^{2} - 9

x = (2 y - 1) (5 y - 6)