What is the axis y=(x-5)^2-1 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=(x-5)^2-1

axis

y = (x - 5)^{2} - 1

x = 5

Solution steps

y = (x - 5)^{2} - 1

Rewrite

y = (x - 5)^{2} - 1

in the standard form:

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, - 1), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 5

y = (x + 1) (2 x + 2)

y = (x - 5)^{2} - 4

y = - 3 x^{2} - 2

y = - \frac{1}{11} (x + 5)^{2} + 5

y = - 2 x + x (x - 2) - 2 x (x - 1) - (x - 3)