What is the axis (x-4)^2=20(y+5) ?

The axis (x-4)^2=20(y+5) is x=4

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axis (x-4)^2=20(y+5)

axis

(x - 4)^{2} = 20 (y + 5)

x = 4

Solution steps

(x - 4)^{2} = 20 (y + 5)

Rewrite

(x - 4)^{2} = 20 (y + 5)

in the standard form:

4 \cdot 5 (y - (- 5)) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, - 5), p = 5

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 4

y = (x + 9) (x + 8)

y^{2} + 12 x - 2 y - 11 = 0

(x + 3)^{2} = 12 y

y = x^{2} - 3 x - 40

x = (3 - y)^{2}