What is the axis 2y^2=-3x ?

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axis 2y^2=-3x

axis

2 y^{2} = - 3 x

y = 0

Solution steps

2 y^{2} = - 3 x

Rewrite

2 y^{2} = - 3 x

in the standard form:

4 (- \frac{3}{8}) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{3}{8}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 3 x^{2} + 6 x - 1

y = 7 x^{2} + 5

y = - x^{2} + 8 x

y = - 16 x^{2} + 40 x + 2

x = - 2 y + y (y - 2) - 2 y (y - 1) - (y - 3)