What is the axis x=(y+1)(y+2) ?

The axis x=(y+1)(y+2) is y=-3/2

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axis x=(y+1)(y+2)

axis

x = (y + 1) (y + 2)

y = - \frac{3}{2}

Solution steps

x = (y + 1) (y + 2)

Rewrite

x = (y + 1) (y + 2)

in the standard form

4 \cdot \frac{1}{4} (x - (- \frac{1}{4})) = (y - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, - \frac{3}{2}), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - \frac{3}{2}

4 x^{2} - 128 y = 0

(y - 3)^{2} = - 8 (x - 4)

y = (x - 13)^{2}

y = x^{2} - 5 x - 84

y = + \frac{1}{4} x^{2} + \frac{2}{3} x - \frac{1}{6}