What is the axis y=(x-13)^2 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=(x-13)^2

axis

y = (x - 13)^{2}

x = 13

Solution steps

y = (x - 13)^{2}

Rewrite

y = (x - 13)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 13)^{2}

Therefore parabola properties are:

(h, k) = (13, 0), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 13

y = x^{2} - 5 x - 84

y = + \frac{1}{4} x^{2} + \frac{2}{3} x - \frac{1}{6}

x = + (y + 1)^{2} - 9

y = x^{2} - 3 x - 10

4 x = y^{2} - 4 y