What is the axis y=-1/2 (x+6)^2+8 ?

The axis y=-1/2 (x+6)^2+8 is x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=-1/2 (x+6)^2+8

axis

y = - \frac{1}{2} (x + 6)^{2} + 8

x = - 6

Solution steps

y = - \frac{1}{2} (x + 6)^{2} + 8

Rewrite

y = - \frac{1}{2} (x + 6)^{2} + 8

in the standard form:

4 (- \frac{1}{2}) (y - 8) = (x - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (- 6, 8), p = - \frac{1}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 6

y = x^{2} + 8 x + 3

y = x^{2} + 3 x

y = \frac{5 x + 3 - x ^{2}}{3}

y = 8 x - x^{2} - 17

y = 10 + 5 x - x^{2}