What is the axis y^2=4*3x-6 ?

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axis y^2=4*3x-6

axis

y^{2} = 4 \cdot 3 x - 6

y = 0

Solution steps

y^{2} = 4 \cdot 3 x - 6

Rewrite

y^{2} = 4 \cdot 3 x - 6

in the standard form:

4 \cdot 3 (x - \frac{1}{2}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, 0), p = 3

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

x^{2} - 10 x - 24 y = - 25 - 24

y \geq x^{2} - 9

y = 4 - 5 x^{2}

y = (x - 6) (x - 5)

(x + 1)^{2} = 2 (y + 2)