What is the vertices 25x^2+9y^2=225 ?

The vertices 25x^2+9y^2=225 is (0,5),(0,-5)

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vertices 25x^2+9y^2=225

vertices

25 x^{2} + 9 y^{2} = 225

(0, 5), (0, - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

25 x^{2} + 9 y^{2} = 225 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 3

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

4 x^{2} - 20 x - 24 y + 97 = 0

x^{2} + y^{2} = 16

9 x^{2} + 4 y^{2} + 36 x - 24 y + 36 = 0

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

What is the vertices 25x^2+9y^2=225 ?
The vertices 25x^2+9y^2=225 is (0,5),(0,-5)