What is the axis y^2=5x+3 ?

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axis y^2=5x+3

axis

y^{2} = 5 x + 3

y = 0

Solution steps

y^{2} = 5 x + 3

Rewrite

y^{2} = 5 x + 3

in the standard form:

4 \cdot \frac{5}{4} (x - (- \frac{3}{5})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{5}, 0), p = \frac{5}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

(y + 4)^{2} = 7 (x - 2)

y = 6 x^{2} + 3 x

y = 4 x - 3 x^{2}

x = y^{2} - 4

y = \frac{2}{3} (x - 1)^{2}