What is the axis y=2x^2-3x-8 ?

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axis y=2x^2-3x-8

axis

y = 2 x^{2} - 3 x - 8

x = \frac{3}{4}

Solution steps

y = 2 x^{2} - 3 x - 8

Rewrite

y = 2 x^{2} - 3 x - 8

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{73}{8})) = (x - \frac{3}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{4}, - \frac{73}{8}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{4}

y = 6 x^{2} + 5 x + 3

y = 6 x^{2} + 5 x + 7

9 x^{2} + 24 x + 72 y + 16 = 0

y = x^{2} + 36

y^{2} = 24 x