What is the axis y=(2x-6)^2 ?

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axis y=(2x-6)^2

axis

y = (2 x - 6)^{2}

x = 3

Solution steps

y = (2 x - 6)^{2}

Rewrite

y = (2 x - 6)^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 0), p = \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = + 2 x^{2} + 8 x + 4

x = 2 y^{2}

y = (5 - x) (2 x - 3)

y = 3 x^{2} - 15 x + 6

x^{2} = - 16 y