What is the axis (y-2)/4-(x^2)/9 =1 ?

The axis (y-2)/4-(x^2)/9 =1 is x=0

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axis (y-2)/4-(x^2)/9 =1

axis

\frac{y - 2}{4} - \frac{x ^{2}}{9} = 1

x = 0

Solution steps

\frac{y - 2}{4} - \frac{x ^{2}}{9} = 1

Rewrite

\frac{y - 2}{4} - \frac{x ^{2}}{9} = 1

in the standard form:

4 \cdot \frac{9}{16} (y - 6) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 6), p = \frac{9}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 2 x^{2} + 24 x - 6

y = (2 x)^{2}

x = + (y + 1)^{2}

- y^{2} + x + 6 y - 14 = 0

y = x^{2} + x - 9