What is the axis y=(2x)^2 ?

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axis y=(2x)^2

axis

y = (2 x)^{2}

x = 0

Solution steps

y = (2 x)^{2}

Rewrite

y = (2 x)^{2}

in the standard form

4 \cdot \frac{1}{16} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

x = + (y + 1)^{2}

- y^{2} + x + 6 y - 14 = 0

y = x^{2} + x - 9

2 y^{2} - x - 12 y + 18 = 0

y = (x + 6) (x - 2)