What is the axis y=(x+6)(x-2) ?

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axis y=(x+6)(x-2)

axis

y = (x + 6) (x - 2)

x = - 2

Solution steps

y = (x + 6) (x - 2)

Rewrite

y = (x + 6) (x - 2)

in the standard form

4 \cdot \frac{1}{4} (y - (- 16)) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 16), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 2

x = (y + 2) (y - 3)

x^{2} - 6 x + 5 y = 34

(x + 3)^{2} = 8 (y - 5)

y = 4 x^{2} - 12 x + 10

y = x^{2} + 3 x + 2