What is the axis x=(y+2)(y-3) ?

The axis x=(y+2)(y-3) is y= 1/2

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axis x=(y+2)(y-3)

axis

x = (y + 2) (y - 3)

y = \frac{1}{2}

Solution steps

x = (y + 2) (y - 3)

Rewrite

x = (y + 2) (y - 3)

in the standard form

4 \cdot \frac{1}{4} (x - (- \frac{25}{4})) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{25}{4}, \frac{1}{2}), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = \frac{1}{2}

x^{2} - 6 x + 5 y = 34

(x + 3)^{2} = 8 (y - 5)

y = 4 x^{2} - 12 x + 10

y = x^{2} + 3 x + 2

y = (2 x + 5) (x + 6)