What is the axis x^2-6x+5y=34 ?

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axis x^2-6x+5y=34

axis

x^{2} - 6 x + 5 y = 34

x = 3

Solution steps

x^{2} - 6 x + 5 y = 34

Rewrite

x^{2} - 6 x + 5 y = 34

in the standard form

4 (- \frac{5}{4}) (y - \frac{43}{5}) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, \frac{43}{5}), p = - \frac{5}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

(x + 3)^{2} = 8 (y - 5)

y = 4 x^{2} - 12 x + 10

y = x^{2} + 3 x + 2

y = (2 x + 5) (x + 6)

y = x^{2} + 3 x + 1