What is the axis y^2=-2x ?

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axis y^2=-2x

axis

y^{2} = - 2 x

y = 0

Solution steps

y^{2} = - 2 x

Rewrite

y^{2} = - 2 x

in the standard form:

4 (- \frac{1}{2}) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{2}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = x^{2} - 3 x - 1

x^{2} - 2 x + 36 y + 28 = 0

y = (x + 1) (x - 5)

x = + (y - 4)^{2} - 5

y = (x - 15)^{2}