What is the axis y^2=-6x ?

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axis y^2=-6x

axis

y^{2} = - 6 x

y = 0

Solution steps

y^{2} = - 6 x

Rewrite

y^{2} = - 6 x

in the standard form:

4 (- \frac{3}{2}) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{3}{2}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y \leq 2 x^{2} - 10 x + 10

y = (x + \frac{1}{2}) (x - \frac{1}{3})

y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

x^{2} = - 8 y

y^{2} + 4 x + 1 = 0