What is the axis x^2=-8y ?

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axis x^2=-8y

axis

x^{2} = - 8 y

x = 0

Solution steps

x^{2} = - 8 y

Rewrite

x^{2} = - 8 y

in the standard form:

4 (- 2) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 2

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y^{2} + 4 x + 1 = 0

y = - \frac{1}{6} x^{2} + 4 x + 10

f (x) = - (x - 9)^{2} - 30

x^{2} - 4 x - 5

y = 5 \cdot (x + 7 + 149) (x + 7 - 149)