What is the axis f(x)=-(x-9)^2-30 ?

The axis f(x)=-(x-9)^2-30 is x=9

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axis f(x)=-(x-9)^2-30

axis

f (x) = - (x - 9)^{2} - 30

x = 9

Solution steps

y = - (x - 9)^{2} - 30

Rewrite

y = - (x - 9)^{2} - 30

in the standard form:

4 (- \frac{1}{4}) (y - (- 30)) = (x - 9)^{2}

Therefore parabola properties are:

(h, k) = (9, - 30), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 9

x^{2} - 4 x - 5

y = 5 \cdot (x + 7 + 149) (x + 7 - 149)

30 x^{2} + 90 x + y + 64 = 0

y = (x - 7) (x - 9)

y = (3 x - 4) (4 x - 3) - 2 x