What is the axis 16x^2-72x-112y=-221 ?

The axis 16x^2-72x-112y=-221 is x= 9/4

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axis 16x^2-72x-112y=-221

axis

16 x^{2} - 72 x - 112 y = - 221

x = \frac{9}{4}

Solution steps

16 x^{2} - 72 x - 112 y = - 221

Rewrite

16 x^{2} - 72 x - 112 y = - 221

in the standard form

4 \cdot \frac{7}{4} (y - \frac{5}{4}) = (x - \frac{9}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{4}, \frac{5}{4}), p = \frac{7}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{9}{4}

x = (4 y + 3) (2 y - 5)

y = - x^{2} + 2 x - 8

y = - \frac{1}{2} (x + 3)^{2} - 1

x = (y - 2)^{2} + 3

y = + (3 - 2 x) (6 - x)