What is the axis x^2=28y ?

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axis x^2=28y

axis

x^{2} = 28 y

x = 0

Solution steps

x^{2} = 28 y

Rewrite

x^{2} = 28 y

in the standard form:

4 \cdot 7 (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 7

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = - 3 [x^{2} - \frac{16}{3} x + \frac{64}{9} - 4 - \frac{64}{9}]

y^{2} - 4 x + 6 y + 17 = 0

x = (y - 2) (y + 1)

y = (x + 4)^{2} + 1

y^{2} - 12 x + 20 = 0