What is the axis y=-3[x^2-16/3 x+64/9-4-64/9 ] ?

The axis y=-3[x^2-16/3 x+64/9-4-64/9 ] is x= 8/3

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axis y=-3[x^2-16/3 x+64/9-4-64/9 ]

axis

y = - 3 [x^{2} - \frac{16}{3} x + \frac{64}{9} - 4 - \frac{64}{9}]

x = \frac{8}{3}

Solution steps

y = - 3 [x^{2} - \frac{16}{3} x + \frac{64}{9} - 4 - \frac{64}{9}]

Rewrite

y = - 3 [x^{2} - \frac{16}{3} x + \frac{64}{9} - 4 - \frac{64}{9}]

in the standard form

4 (- \frac{1}{12}) (y - \frac{100}{3}) = (x - \frac{8}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{8}{3}, \frac{100}{3}), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{8}{3}

y^{2} - 4 x + 6 y + 17 = 0

x = (y - 2) (y + 1)

y = (x + 4)^{2} + 1

y^{2} - 12 x + 20 = 0

y = - 3 x^{2} - 2 x

What is the axis y=-3[x^2-16/3 x+64/9-4-64/9 ] ?
The axis y=-3[x^2-16/3 x+64/9-4-64/9 ] is x= 8/3