What is the axis y=-3x^2-2x ?

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axis y=-3x^2-2x

axis

y = - 3 x^{2} - 2 x

x = - \frac{1}{3}

Solution steps

y = - 3 x^{2} - 2 x

Rewrite

y = - 3 x^{2} - 2 x

in the standard form

4 (- \frac{1}{12}) (y - \frac{1}{3}) = (x - (- \frac{1}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{3}, \frac{1}{3}), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{1}{3}

x = y^{2} - 4 y + 4

(y + 9)^{2} = - 44 (x - 1)

y = 5 x^{2} + 4

y = 5 x^{2} + 3

x = + (y + 5)^{2} + 3