What is the axis x=+(y+11)^2-14 ?

The axis x=+(y+11)^2-14 is y=-11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis x=+(y+11)^2-14

axis

x = + (y + 11)^{2} - 14

y = - 11

Solution steps

x = (y + 11)^{2} - 14

Rewrite

x = (y + 11)^{2} - 14

in the standard form:

4 \cdot \frac{1}{4} (x - (- 14)) = (y - (- 11))^{2}

Therefore parabola properties are:

(h, k) = (- 14, - 11), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 11

y = x^{2} - 3 x + 28

y = (x + 1) x

y = \frac{2 - x ^{2} + 2 x}{3}

y = x^{2} + 2 x - 12

y = x^{2} - 2 x - 4