What is the axis y=x^2-3x+28 ?

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axis y=x^2-3x+28

axis

y = x^{2} - 3 x + 28

x = \frac{3}{2}

Solution steps

y = x^{2} - 3 x + 28

Rewrite

y = x^{2} - 3 x + 28

in the standard form

4 \cdot \frac{1}{4} (y - \frac{103}{4}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{103}{4}), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

y = (x + 1) x

y = \frac{2 - x ^{2} + 2 x}{3}

y = x^{2} + 2 x - 12

y = x^{2} - 2 x - 4

(y - 1)^{2} = - 6 (x + 2)