What is [(2*10^0)/ 1/3 ]+8 ?

The solution to [(2*10^0)/ 1/3 ]+8 is 14

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[(2*10^0)/ 1/3 ]+8

[(2 \cdot 1 0^{0}) / \frac{1}{3}] + 8

14

Solution steps

[(2 \cdot 1 0^{0}) / \frac{1}{3}] + 8

Follow the PEMDAS order of operations

Calculate within parentheses

[(2 \cdot 1 0^{0}) / \frac{1}{3}] : 6

(2 \cdot 1 0^{0}) / \frac{1}{3}

Calculate within parentheses

(2 \cdot 1 0^{0}) : 2

2 \cdot 1 0^{0}

Calculate exponents

1 0^{0} : 1

1 0^{0}

1 0^{0} = 1

= 1

= 2 \cdot 1

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 2

= 2/ \frac{1}{3}

Multiply and divide (left to right)

2/ \frac{1}{3} : 6

2/ \frac{1}{3}

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} \div \frac{1}{3}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{2}{1} \cdot \frac{3}{1}

Apply rule

\frac{a}{1} = a

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

= 6

= 6 + 8

Add and subtract (left to right)

6 + 8 : 14

6 + 8

6 + 8 = 14

= 14

= 14

\frac{1}{6} - 8 + \frac{3}{2}

(1/2) - 1

3 (- 2) - 5 (+ 3) + 4 (- 3) - 3

\frac{12}{11} \cdot 7 - 12

80 \div 4 - 2 (2 + 1)^{2}