What is 7+(5-9)^2+3(16\div 8) ?

The solution to 7+(5-9)^2+3(16\div 8) is 29

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7+(5-9)^2+3(16\div 8)

7 + (5 - 9)^{2} + 3 (16 \div 8)

29

Solution steps

7 + (5 - 9)^{2} + 3 (16 \div 8)

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 9) : - 4

5 - 9

5 - 9 = - 4

= - 4

= 7 + (- 4)^{2} + 3 (16 \div 8)

Calculate within parentheses

(16 \div 8) : 2

16 \div 8

16 \div 8 = 2

= 2

= 7 + (- 4)^{2} + 3 \cdot 2

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 7 + 16 + 3 \cdot 2

Multiply and divide (left to right)

3 \cdot 2 : 6

3 \cdot 2

3 \cdot 2 = 6

= 6

= 7 + 16 + 6

Add and subtract (left to right)

7 + 16 + 6 : 29

7 + 16 + 6

7 + 16 = 23

= 23 + 6

23 + 6 = 29

= 29

= 29

- 18 (1) + 2 (13)

(3 - 2 + 1) \times 10 + 2 \times (- 3 + 3)

2^{2} \div 2

3 (5 + 20)

9^{2} - (5 + 2 \cdot 6^{2})