What is -3(3)^2+4(3) ?

The solution to -3(3)^2+4(3) is -15

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-3(3)^2+4(3)

- 3 (3)^{2} + 4 (3)

- 15

Solution steps

- 3 (3)^{2} + 4 (3)

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= - 3 \cdot 9 + 4 (3)

Multiply and divide (left to right)

- 3 \cdot 9 : - 27

- 3 \cdot 9

- 3 \cdot 9 = - 27

= - 27

= - 27 + 4 (3)

Multiply and divide (left to right)

4 (3) : 12

4 (3)

Apply rule:

(a) = a

(3) = 3

= 4 \cdot 3

Multiply the numbers:

4 \cdot 3 = 12

= 12

= - 27 + 12

Add and subtract (left to right)

- 27 + 12 : - 15

- 27 + 12

- 27 + 12 = - 15

= - 15

= - 15

\frac{1}{3} 21 - 1 - \frac{1}{2} 12

32 \times 5 + (28 \div 7) \div 5 \times 71 (58 - 18)

30 \div 3 \times (5 - 2)

\frac{13}{16} - (\frac{1}{4} - \frac{3}{8})

(2 \times 3)^{4}