What is [(2+5+2+5^2)+2^3]\div 6 ?

The solution to [(2+5+2+5^2)+2^3]\div 6 is 7

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[(2+5+2+5^2)+2^3]\div 6

[(2 + 5 + 2 + 5^{2}) + 2^{3}] \div 6

7

Solution steps

[(2 + 5 + 2 + 5^{2}) + 2^{3}] \div 6

Follow the PEMDAS order of operations

Calculate within parentheses

[(2 + 5 + 2 + 5^{2}) + 2^{3}] : 42

= 42 \div 6

Multiply and divide (left to right)

42 \div 6 : 7

= 7

4^{2} - 4 \times 4

- 5 (- 2)^{2} - 20 (- 2) - 26

(\frac{13}{5} - \frac{1}{2}) + \frac{1}{6}

- (- (- 7^{2})^{3})^{2}

3 (1)^{2} - 6 (1) - 7