What is [6+4[9-5(10-12)]+9-5]+18 ?

The solution to [6+4[9-5(10-12)]+9-5]+18 is 104

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[6+4[9-5(10-12)]+9-5]+18

[6 + 4 [9 - 5 (10 - 12)] + 9 - 5] + 18

104

Solution steps

[6 + 4 [9 - 5 (10 - 12)] + 9 - 5] + 18

Follow the PEMDAS order of operations

Calculate within parentheses

[6 + 4 [9 - 5 (10 - 12)] + 9 - 5] : 86

6 + 4 [9 - 5 (10 - 12)] + 9 - 5

Calculate within parentheses

[9 - 5 (10 - 12)] : 19

9 - 5 (10 - 12)

Calculate within parentheses

(10 - 12) : - 2

10 - 12

10 - 12 = - 2

= - 2

= 9 - 5 (- 2)

Multiply and divide (left to right)

5 (- 2) : - 10

5 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 2) = - 5 \cdot 2 = - 10

= - 10

= 9 - (- 10)

Add and subtract (left to right)

9 - (- 10) : 19

9 - (- 10)

Apply rule

- (- a) = + a

- (- 10) = + 10

= 9 + 10

9 + 10 = 19

= 19

= 19

= 6 + 4 \cdot 19 + 9 - 5

Multiply and divide (left to right)

4 \cdot 19 : 76

4 \cdot 19

4 \cdot 19 = 76

= 76

= 6 + 76 + 9 - 5

Add and subtract (left to right)

6 + 76 + 9 - 5 : 86

6 + 76 + 9 - 5

6 + 76 = 82

= 82 + 9 - 5

82 + 9 = 91

= 91 - 5

91 - 5 = 86

= 86

= 86

= 86 + 18

Add and subtract (left to right)

86 + 18 : 104

86 + 18

86 + 18 = 104

= 104

= 104

\frac{1}{3} \times 4 - 3

3 \div 2 \times 125

\frac{4}{3} \cdot 7^{3}

36 \div (8 \times 2 - (30 \div 5) + 4 \times 2)

5 ((- 5) - 1)

What is [6+4[9-5(10-12)]+9-5]+18 ?
The solution to [6+4[9-5(10-12)]+9-5]+18 is 104