What is 9-(-11/3+2) ?

The solution to 9-(-11/3+2) is 10 2/3

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Popular >

9-(-11/3+2)

Solution

9 - (- \frac{11}{3} + 2)

Solution

10 \frac{2}{3}

Solution steps

9 - (- \frac{11}{3} + 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(- \frac{11}{3} + 2) : - \frac{5}{3}

- \frac{11}{3} + 2

- \frac{11}{3} + 2 = - \frac{5}{3}

- \frac{11}{3} + 2

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= \frac{2 \cdot 3}{3} - \frac{11}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 - 11}{3}

2 \cdot 3 - 11 = - 5

2 \cdot 3 - 11

Multiply the numbers:

2 \cdot 3 = 6

= 6 - 11

Subtract the numbers:

6 - 11 = - 5

= - 5

= \frac{- 5}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{5}{3}

= - \frac{5}{3}

= 9 - (- \frac{5}{3})

Add and subtract (left to right)

9 - (- \frac{5}{3}) : \frac{32}{3}

9 - (- \frac{5}{3})

Apply rule

- (- a) = + a

- (- \frac{5}{3}) = + \frac{5}{3}

= 9 + \frac{5}{3}

9 + \frac{5}{3} = \frac{32}{3}

9 + \frac{5}{3}

Convert element to fraction:

9 = \frac{9 \cdot 3}{3}

= \frac{9 \cdot 3}{3} + \frac{5}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{9 \cdot 3 + 5}{3}

9 \cdot 3 + 5 = 32

9 \cdot 3 + 5

Multiply the numbers:

9 \cdot 3 = 27

= 27 + 5

Add the numbers:

27 + 5 = 32

= 32

= \frac{32}{3}

= \frac{32}{3}

= \frac{32}{3}

Convert improper fractions to mixed numbers:

\frac{32}{3} = 10 \frac{2}{3}

\frac{32}{3} = 10

Remainder

2

\frac{32}{3}

Write the problem in long division format

3 \overline{∣ 32}

Divide

3

3

to get

1

Divide

3

3

to get

1

1 3 \overline{∣ 32}

Multiply the quotient digit

(1)

by the divisor

3

1 3 \overline{∣ 32} \underline{3}

Subtract

3

from

3

1 3 \overline{∣ 32} \underline{3} 0

Bring down the next number of the dividend

1 3 \overline{∣ 32} \underline{3} 02

1 3 \overline{∣ 32} \underline{3} 02

Divide

2

3

to get

0

Divide

2

3

to get

0

10 3 \overline{∣ 32} \underline{3} 02

Multiply the quotient digit

(0)

by the divisor

3

10 3 \overline{∣ 32} \underline{3} 02 \underline{0}

Subtract

0

from

2

10 3 \overline{∣ 32} \underline{3} 02 \underline{0} 2

10 3 \overline{∣ 32} \underline{3} 02 \underline{0} 2

The solution for Long Division of

\frac{32}{3}

10

with remainder of

2

10 Remainder 2

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{32}{3} = 10 \frac{2}{3}

= 10 \frac{2}{3}

= 10 \frac{2}{3}

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3 (- 2)^{2} - 4 (- 2) + 2

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4 \cdot 1 + 9^{2}

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- 2 \times [- 3 (5 + 4 - 3 - 6) - (2 + 4 + 8 - 9)] + 7

Frequently Asked Questions (FAQ)

What is 9-(-11/3+2) ?
The solution to 9-(-11/3+2) is 10 2/3