What is -2^2+9^2-10\times 5 ?

The solution to -2^2+9^2-10\times 5 is 27

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-2^2+9^2-10\times 5

- 2^{2} + 9^{2} - 10 \cdot 5

27

Solution steps

- 2^{2} + 9^{2} - 10 \cdot 5

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

= - 4 + 9^{2} - 10 \cdot 5

Calculate exponents

9^{2} : 81

= - 4 + 81 - 10 \cdot 5

Multiply and divide (left to right)

10 \cdot 5 : 50

= - 4 + 81 - 50

Add and subtract (left to right)

- 4 + 81 - 50 : 27

= 27

35 - 8 - (2 \times 1) + 5 \times (4 - 12 \div 6)

440 - (30 + 6 (19 - 12))

- (- (8 - 19) - 25) + (- (- 50 + 40 - 15))

6 \cdot 5^{2}

3 - [(3 - 4) + 5 - (7 + 8) - (15 - 14) + (7 - 8)]