The solution to 4+(3+4)^2 is 53

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4+(3+4)^2

Solution

4 + (3 + 4)^{2}

53

Solution steps

4 + (3 + 4)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(3 + 4) : 7

3 + 4

3 + 4 = 7

= 7

= 4 + 7^{2}

Calculate exponents

7^{2} : 49

7^{2}

7^{2} = 49

= 49

= 4 + 49

Add and subtract (left to right)

4 + 49 : 53

4 + 49

4 + 49 = 53

= 53

= 53

- 8 - (- 6) - (- 4) - 1

3 - 4^{2}

3^{2} - 6 (3) - 5

3 (- 2) + 6

(- 3)^{3} \div (6 \times (- 7))