The solution to 2(0-1)^2+1 is 3

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2(0-1)^2+1

Solution

2 (0 - 1)^{2} + 1

3

Solution steps

2 (0 - 1)^{2} + 1

Follow the PEMDAS order of operations

Calculate within parentheses

(0 - 1) : - 1

0 - 1

0 - 1 = - 1

= - 1

= 2 (- 1)^{2} + 1

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 2 \cdot 1 + 1

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 2 + 1

Add and subtract (left to right)

2 + 1 : 3

2 + 1

2 + 1 = 3

= 3

= 3

3 \times 10 + 8 - 4^{2}

4 \div 9 - 1 \div 9

(- 9) - (- 8) + 2 \times 4^{2}

\frac{1}{2} (2) + 1

\frac{1}{2} \cdot 4^{0}