What is (-7)^2+4(-7)-2 ?

The solution to (-7)^2+4(-7)-2 is 19

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(-7)^2+4(-7)-2

(- 7)^{2} + 4 (- 7) - 2

19

Solution steps

(- 7)^{2} + 4 (- 7) - 2

Follow the PEMDAS order of operations

Calculate exponents

(- 7)^{2} : 49

(- 7)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 7)^{2} = 7^{2} = 49

= 49

= 49 + 4 (- 7) - 2

Multiply and divide (left to right)

4 (- 7) : - 28

4 (- 7)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 7) = - 4 \cdot 7 = - 28

= - 28

= 49 - 28 - 2

Add and subtract (left to right)

49 - 28 - 2 : 19

49 - 28 - 2

49 - 28 = 21

= 21 - 2

21 - 2 = 19

= 19

= 19

\frac{5}{6} (3)^{1}

[(5 + 2) 3 + (6 - 1) 5] [(8 + 6) 3 - (4 - 1) 2]

- 7 (88) + 1

\frac{1}{7} \times (3 - \frac{1}{5})

(- 6 - 2)^{2}