What is -(3-9)^2-12\div (15\div 5)-(21\div 7)^3 ?

The solution to -(3-9)^2-12\div (15\div 5)-(21\div 7)^3 is -67

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-(3-9)^2-12\div (15\div 5)-(21\div 7)^3

- (3 - 9)^{2} - 12 \div (15 \div 5) - (21 \div 7)^{3}

- 67

Solution steps

- (3 - 9)^{2} - 12 \div (15 \div 5) - (21 \div 7)^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - 9) : - 6

3 - 9

3 - 9 = - 6

= - 6

= - (- 6)^{2} - 12 \div (15 \div 5) - (21 \div 7)^{3}

Calculate within parentheses

(15 \div 5) : 3

15 \div 5

15 \div 5 = 3

= 3

= - (- 6)^{2} - 12 \div 3 - (21 \div 7)^{3}

Calculate within parentheses

(21 \div 7) : 3

21 \div 7

21 \div 7 = 3

= 3

= - (- 6)^{2} - 12 \div 3 - 3^{3}

Calculate exponents

(- 6)^{2} : 36

(- 6)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2} = 36

= 36

= - 36 - 12 \div 3 - 3^{3}

Calculate exponents

3^{3} : 27

3^{3}

3^{3} = 27

= 27

= - 36 - 12 \div 3 - 27

Multiply and divide (left to right)

12 \div 3 : 4

12 \div 3

12 \div 3 = 4

= 4

= - 36 - 4 - 27

Add and subtract (left to right)

- 36 - 4 - 27 : - 67

- 36 - 4 - 27

- 36 - 4 = - 40

= - 40 - 27

- 40 - 27 = - 67

= - 67

= - 67

- (5 + 3) + 6

- 1^{3} - 3 (- 1)^{2} + (- 1) - 2

10 (- 1)^{2}

1 + 3 \div 7

3 \cdot 2^{2} + 4 (3 - 1)

What is -(3-9)^2-12\div (15\div 5)-(21\div 7)^3 ?
The solution to -(3-9)^2-12\div (15\div 5)-(21\div 7)^3 is -67