What is 2(-1)^2+6(-1)+2 ?

The solution to 2(-1)^2+6(-1)+2 is -2

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2(-1)^2+6(-1)+2

2 (- 1)^{2} + 6 (- 1) + 2

- 2

Solution steps

2 (- 1)^{2} + 6 (- 1) + 2

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 2 \cdot 1 + 6 (- 1) + 2

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 2 + 6 (- 1) + 2

Multiply and divide (left to right)

6 (- 1) : - 6

6 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

6 (- 1) = - 6 \cdot 1 = - 6

= - 6

= 2 - 6 + 2

Add and subtract (left to right)

2 - 6 + 2 : - 2

2 - 6 + 2

2 - 6 = - 4

= - 4 + 2

- 4 + 2 = - 2

= - 2

= - 2

(7)^{2} - 22 (7) + 120

7^{2} - 40 + 18 \div 3^{2} - 1 0^{0}

\frac{1}{3} \times 5^{2} \times 10

- 19 + (- 9 \times 12 + 8) \div (- 8 + 33)

2 (2)^{2} + 4 (2)