What is 6\times 5+(-4)^2 ?

The solution to 6\times 5+(-4)^2 is 46

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6\times 5+(-4)^2

6 \cdot 5 + (- 4)^{2}

46

Solution steps

6 \cdot 5 + (- 4)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 6 \cdot 5 + 16

Multiply and divide (left to right)

6 \cdot 5 : 30

6 \cdot 5

6 \cdot 5 = 30

= 30

= 30 + 16

Add and subtract (left to right)

30 + 16 : 46

30 + 16

30 + 16 = 46

= 46

= 46

17 + 34 - 2

(4)^{2} - 5 (4) + 1

6 \div 7 \times 3 \div 4

\frac{2}{3} - 10 - \frac{5}{4}

- 5 + 4 (3 - (2 - 5))