What is (8(9-4))/(2+6^2-18) ?

The solution to (8(9-4))/(2+6^2-18) is 2

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(8(9-4))/(2+6^2-18)

\frac{8 ( 9 - 4 )}{2 + 6 ^{2} - 18}

2

Solution steps

\frac{8 ( 9 - 4 )}{2 + 6 ^{2} - 18}

Solve

8 (9 - 4) : 40

Follow the PEMDAS order of operations

Calculate within parentheses

(9 - 4) : 5

9 - 4

9 - 4 = 5

= 5

= 8 \cdot 5

Multiply and divide (left to right)

8 \cdot 5 : 40

8 \cdot 5

8 \cdot 5 = 40

= 40

= 40

Solve

2 + 6^{2} - 18 : 20

Follow the PEMDAS order of operations

Calculate exponents

6^{2} : 36

6^{2}

6^{2} = 36

= 36

= 2 + 36 - 18

Add and subtract (left to right)

2 + 36 - 18 : 20

2 + 36 - 18

2 + 36 = 38

= 38 - 18

38 - 18 = 20

= 20

= 20

= \frac{40}{20}

Divide the numbers:

\frac{40}{20} = 2

= 2

2^{4} + (- 2)^{4} - 2^{4} + 2^{3} + 3^{3} - 5^{0}

3^{2} + 22 - (- 45)

5 (- 2 - 7)^{2} - 7

\frac{13 + 7 ^{2} \div 7}{9 - 20 \div 4 - 16}

3^{3} \times 5^{0}