What is 3(-1)^2-4(-1)-4 ?

The solution to 3(-1)^2-4(-1)-4 is 3

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3(-1)^2-4(-1)-4

3 (- 1)^{2} - 4 (- 1) - 4

3

Solution steps

3 (- 1)^{2} - 4 (- 1) - 4

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 3 \cdot 1 - 4 (- 1) - 4

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= 3 - 4 (- 1) - 4

Multiply and divide (left to right)

4 (- 1) : - 4

4 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 1) = - 4 \cdot 1 = - 4

= - 4

= 3 - (- 4) - 4

Add and subtract (left to right)

3 - (- 4) - 4 : 3

3 - (- 4) - 4

Apply rule

- (- a) = + a

- (- 4) = + 4

= 3 + 4 - 4

3 + 4 = 7

= 7 - 4

7 - 4 = 3

= 3

= 3

3^{2} + 5 \times 2 - 9 - 12 \div 3 + 2

3 (- 2)^{2} - 2 (- 2) + 1

(8 + 3 \times 2) - (4 \times (5 + 3) - (- 12 - 3) + 125)

(- 3)^{4} - 4 (- 3)^{2}

(- 16 - (- 3)) \times (- 2)