What is the derivative of f(x)= 3/(x^4) ?

The derivative of f(x)= 3/(x^4) is -(12)/(x^5)

What is the first derivative of f(x)= 3/(x^4) ?

The first derivative of f(x)= 3/(x^4) is -(12)/(x^5)

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derivative of

f (x) = \frac{3}{x ^{4}}

- \frac{12}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 4 x^{- 4 - 1})

Simplify

3 (- 4 x^{- 4 - 1}) : - \frac{12}{x ^{5}}

= - \frac{12}{x ^{5}}

y = x^{(\frac{7}{3})}

x^{2} + 3 x - 5, at x = 1

y = 7 x

x + \frac{1}{x}

y = 5 x^{2}

What is the derivative of f(x)= 3/(x^4) ?
The derivative of f(x)= 3/(x^4) is -(12)/(x^5)
What is the first derivative of f(x)= 3/(x^4) ?
The first derivative of f(x)= 3/(x^4) is -(12)/(x^5)