What is the derivative of x^2-3x+4 ?

The derivative of x^2-3x+4 is 2x-3

What is the first derivative of x^2-3x+4 ?

The first derivative of x^2-3x+4 is 2x-3

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derivative of

x^{2} - 3 x + 4

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 2 x - 3 + 0

Simplify

= 2 x - 3

f (x) = \frac{x}{x ^{2} + 1}

(4, \frac{π}{2})

(3, 0), (0, - 12)

f (x) = 1

(2, 5), (- 3, - 6)

What is the derivative of x^2-3x+4 ?
The derivative of x^2-3x+4 is 2x-3
What is the first derivative of x^2-3x+4 ?
The first derivative of x^2-3x+4 is 2x-3