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midpoint
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f=-2derivative of f(x)=3-4x,\at x=8derivative of derivative of f(x)= 1/(3x^2)-5/(2x)+8x-6derivative of cartesian (-3, pi/6)polar to cartesian tangent of y^3+xy^2-5=x+3y^2,\at x=3tangent of
Frequently Asked Questions (FAQ)
What is the midpoint (2,5),(-3,-6) ?
The midpoint (2,5),(-3,-6) is (-1/2 ,-1/2)