What is the tangent of y=x^3-2x^2+4,(2,4) ?

The tangent of y=x^3-2x^2+4,(2,4) is y=4x-4

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tangent of y=x^3-2x^2+4,(2,4)

tangent of

y = x^{3} - 2 x^{2} + 4, (2, 4)

y = 4 x - 4

Solution steps

Find the slope of

y = x^{3} - 2 x^{2} + 4 : \frac{d y}{d x} = 3 x^{2} - 4 x

Compute the slope of

y = x^{3} - 2 x^{2} + 4

(2, 4) : m = 4

Find the line with slope m=

4

and passing through

(2, 4) : y = 4 x - 4

y = 4 x - 4

e^{x^{2}}

3 x + y - 15 = 0

f (x) = 2 x^{2} + 7 x - 9, at x = - 3

f (x) = (2 x + 1)^{2}

(2, - 23)

What is the tangent of y=x^3-2x^2+4,(2,4) ?
The tangent of y=x^3-2x^2+4,(2,4) is y=4x-4